The largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is ✅ Đầy đủ
Kinh Nghiệm về The largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is Chi Tiết
Cao Nguyễn Bảo Phúc đang tìm kiếm từ khóa The largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is được Cập Nhật vào lúc : 2022-10-03 06:50:29 . Với phương châm chia sẻ Bí kíp về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi đọc tài liệu vẫn ko hiểu thì hoàn toàn có thể lại phản hồi ở cuối bài để Admin lý giải và hướng dẫn lại nha.hello student the question given year is find the largest number that will divide 398 436 and 542 living the remainder 7 11 and 15 respectively so fast working to the t98 ok 398 when divided by largest number ok it gives the reminder that is 7 first we will do a fraction of days to number 98 - 7 that is equal to 391 similarly when we divide 4:30 by the largest number ok give the reminder 11 that means 436 -11 equal to 4 25 / divide 542 by the largest number it gives the reminder 1542 -15 equal to word file
Nội dung chính-
Find the largest number that will divide $398$, $436$, and $542$ leaving remainders $7$, $11$, and $15$ respectively.
Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively.
What is the HCF of 398 436 and 542?What is the largest number that divides 70 and 125 leaving remainders?How do you find the largest positive integer?What is the name given to the largest positive integer that divides given two positive integers completely?
27 sunao you have to do to find out the HCF of these three number 391 425 and 527 who have to find HCF of 91 425 and 527 calculate HCF of these three number the SF comes out after Cup finding essay answer which comes out this is the largest number which divides 398 436 1542 which are and giving the reminder 11 and 15 find out of these three number do before finding HCF of this không lấy phí number up to prime factorization this three numbers that 391 equal to hack Android 17 X 22 23 24 25 equal to I can write s 5 to the power 2 x
527 equal to I can write a 17 X 31 ok this is the age of the prime factors of a number 394 25 and 527 HCF of this train number means what the common prime factor of lowest power of common prime factor theorem and factor is 17 power is power is one that means 17 to the power 1 equal to 17 their HCF of 391 425 527 equal to 17 and this is the largest number which divides 398 436 and 542 leaving the reminder 7:15 a.m.
find the largest number that will divide the number living reminder 71115 reminders mein agar kar de tu jo number perfectly divide Karega mera number kya hai yahan Mera annual hai N Si 98 - Jo reminder Mein nikal Dunga that is aaega 91 score a perfectly divide Karega with zero reminder and 24 36 - Kitna 11 3542 -15 that is 527 ticket office mein kya karenge ab main theek hai ab isko Dekhenge Ham
2370 in 25 and 35 2731 into 17 Jo in Mein sabse highest Hoga highest common factor into your number ka Vahi number Vahi largest number hoga jo jo is divide karne par mujhe Anda deti hai kya iska ismein Agaram common number 217 Hamen sirf common number Milta Hai
Find the largest number that will divide $398$, $436$, and $542$ leaving remainders $7$, $11$, and $15$ respectively.
Answer
Verified
Hint: Here we go through by finding the HCF of the number after subtracting their remainder because we know that The largest or greatest factor common to any two or more given natural numbers is termed as HCF of given numbers. Also known as GCD (Greatest Common Divisor).
Complete answer:
Here in this question for finding the numbers that will divide $398$, $436$, and $542$ leaving remainders $7$, $11$, and $15$ respectively we have to first subtract the remainder of the following. By this step, we find the highest common factor of the numbers.
And then the required number is the HCF of the following numbers that are formed when the remainder are subtracted from them.
Clearly, the required number is the HCF of the numbers $398−7=391,436−11=425$ and, $542−15=527$ .
We will find the HCF of $391$, $425$ and $527$ by prime factorization method.
$391 = 17 times 23$
$425 = 5^2 times 17$
$527 = 17 times 31$
Hence, HCF of $391$, $4250$, and $527$ is $17$ because the greatest common factor from all the numbers is 17 only.
So we can say that the largest number that will divide $398$, $436$ and $542$ leaving remainders $7$, $11$ and $15$ respectively is $17$.
Note: Whenever we face such a type of question the key concept for solving this question is whenever in the question it is asking about the largest number it divides. You should always think about the highest common factor i.e. HCF. we have to subtract remainder because you have to find a factor that means it should be perfectly divisible so to make divisible we subtract remainder. because remainder is the extra number so on subtracting remainder it becomes divisible.
Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively.
Answer
Verified
Hint- Here, we will proceed by subtracting the given remainders from the given numbers and then, finding out the highest common factor (HCF) of the three numbers will be obtained from the last step.Complete step-by-step answer:
The given numbers are 398, 436 and 542 which when divided by a number (largest) leaves remainders as 7, 11 and 15 respectively.
So, for the numbers which will be exactly divisible by the largest number (which needs to be found), we will subtract the
remainders 7, 11 and 15 from 398, 436 and 542 respectively.
(398 – 7) = 391, (436 – 11) = 425 and (542 – 15) = 527
According to prime factorisation, the numbers 391, 425 and 527 can be represented as the product of their prime factors as under
$
391 = 17 times 23 \
425 = 5 times 5 times 17 \
527 = 17 times 31 \
$
Clearly, we can see that 17 is the only prime factor which is common to all the numbers i.e., 391, 425 and
527.
The highest common factor (HCF) of the numbers 391, 425 and 527 will be given by taking the product of all the common prime factors. Here, there is only one common prime factor that’s why the HCF will be equal to that common prime factor.
HCF of 391, 425 and 527 = 17
This number i.e., 17 (this is the largest number) will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively
Therefore, the largest required number that will divide 398, 436 and 542 leaving remainders
7, 11 and 15 respectively is 17.
Note- In this particular problem, the numbers 391, 425 and 527 will be exactly divisible by the number 17 because 17 is a prime factor (or prime number) which when divided by these numbers i.e., 391, 425 and 527 leaves zero as the remainder since, the remainders which this number 17 leaves when divided by 398, 436 and 542 are already subtracted.
What is the HCF of 398 436 and 542?
What is HCF of 398, 436 and 542? Answer: HCF of 398, 436 and 542 is 2.What is the largest number that divides 70 and 125 leaving remainders?
Hence, the largest number that divides 70 and 125 , leaving remainders 5 and 8 , respectively is 13 .How do you find the largest positive integer?
Then we will take HCF of all the three numbers formed to find the largest positive integer that will divide all 3 numbers as HCF itself stands for 'Highest Common Factor'. 398 – 7 = 391, 436 – 11 = 425, 542 – 15 = 527.What is the name given to the largest positive integer that divides given two positive integers completely?
Definition(s): The largest positive integer that divides each of two or more positive integers without a remainder. Tải thêm tài liệu liên quan đến nội dung bài viết The largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is